Question

1 molar mixture of He and

CH4

is containing in a

vessel at 20 bar pressure. Due to a hole in the

vessel, the gas mixture leaks out, what is the

composition of the mixture effusing out initially?​

Answer 1

Answer:

Hey dear,

● Answer -

He : CH4 = 8 : 1.

● Explaination -

# Given -

P = 20 bar

n1/n2 = 4

# Explanation -

For He,

M(He) = 4

P(He) = P.X(He)

P(He) = 20 × 4 / (4+1) P(He) = 16 bar

For CH4,

M(CH4) = 16

P(CH4) = P.X(CH4)

P(CH4) = 20 × 1 / (4+1)

P(CH4) = 4 bar

Rate of diffusion is given by -

r1/r2 = √[M(CH4)/M(He)] × P(He)/P(CH4)

r1/r2 = √(16/4) × 16/4

r1/r2 = 8

Therefore, composition of initial mixture is He : CH4 = 8 : 1.