Chemistry, asked by rupal4883, 10 months ago

1 mole Caco3(s) is heated in 11.2 lit vessels
so that equilibrium is established at 819 K .
If Kp for Caco3 = Cao+ CO2 at this
temperature is 2 atm equilibrium
concentration of CO2, in mol-lit-1
1) 1/3
2) 1/112
3) 1/33.6
4) 1/22.4

Answers

Answered by saumyarupsen7
12

Answer:

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Answered by payalchatterje
1

Answer:

The concdntration of CO₂ is 1/33.6 mol/lit.

Option 3 is right.

Explanation:

CaCO₃→CaO + CO₂

Dₙg = 1 mole

Kₚ =K₍c₎ RT ,here R= 0.0821 and T= 819k

K₍c₎=Kₚ/RT=2/(0.0821x81)=0.029

K₍c₎= [CO₂]

[CO₂]= 0.029=1/33.6 mol/lit

Therefore , the equilibrium concentration of CO₂ is 1/33.6 mol/lit

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