1 mole Caco3(s) is heated in 11.2 lit vessels
so that equilibrium is established at 819 K .
If Kp for Caco3 = Cao+ CO2 at this
temperature is 2 atm equilibrium
concentration of CO2, in mol-lit-1
1) 1/3
2) 1/112
3) 1/33.6
4) 1/22.4
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Answer:
The concdntration of CO₂ is 1/33.6 mol/lit.
Option 3 is right.
Explanation:
CaCO₃→CaO + CO₂
Dₙg = 1 mole
Kₚ =K₍c₎ RT ,here R= 0.0821 and T= 819k
K₍c₎=Kₚ/RT=2/(0.0821x81)=0.029
K₍c₎= [CO₂]
[CO₂]= 0.029=1/33.6 mol/lit
Therefore , the equilibrium concentration of CO₂ is 1/33.6 mol/lit
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