Question

1 mole of A and 1 mole of B are made to form A2B3. Identify the limiting reagent and calculate the moles of A2B3 formed.
Equation- 2A + 3B -> A2B3

Answer 1

Answer:

Explanation:

2A + 3B ==> A2B3

1 mol A x (1 mol A2B3/2mols A) = 1 x 1/2 = 1/2 mol A2B3 formed.

2mols B x (1 mol A2B3/3mols B) = 2 x 1/3 = 2/3 mol A2B3 formed.

In limiting reagent problems, the SMALLER number is ALWAYS the correct value and the reagent producing that number is the limiting reagent. So which is smaller, 1/2 or 2/3.