1 mole of a are mixed with 2.2 mole of b and the mixture is then kept in a 1 l vessel till the equilibrium a + 2b ⇔ 2c + d is reached. At equilibrium 0.2 moles of c are formed. The equilibrium constant for the reaction is
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When 1 mole of A are mixed with 1 mole of B, 2 moles of C are formed according to the reaction A+B=C+D. What is the equilibrium constant?
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5 ANSWERS
Shubh Jani
Shubh Jani, A Student
Answered Apr 20, 2017
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To calculate an equilibrium constant the reaction must be a reversible reaction.
Let's consider A+B=C a reversible reaction.
Let the initial concentrations of A and B be '1'. There will be ‘0’ concentration of product as the state is initial.
Now at equilibrium, the concentration of A and B changes to '1-x', as product produces is referred to be 'x'.
As we know, the product is of two moles therefore x=2…
Now, Equilibrium constant (k) is the ratio of product of concentration of product to the product of concentration of reactants at equilibrium.
K = [C]² / [A][B]
K = x² / (1-x)(1-x)
K = 2² / (1–2)(1–2)
So, K=4
The unit of Equilibrium constant depends upon the product and reactants, therefore in this case there is no unit.
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Anurag Tiwari
Anurag Tiwari, 1st year, chemical Engineering
Answered Apr 15, 2017
A + B = C + D
1 1 0 0 (initially)
1-x 1-x x x ( at eq)
Given moles of C :x=2
Hence equilibrium constant = [C][D]/[A][B]
2*2/(1–2)(1–2) = 4
K = 4
2.8k Views · View Upvoters · Answer requested by Devashmita Sinha
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Kundan Agrawal
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Kritika Choudhary
Kritika Choudhary, Bsc Mathematics Major & Physics and Chemistry, Govt Post Graduate College Bilaspur (2018)
Answered Oct 12
A + B = C + D
1 1 0 0 (initially)
1-x 1-x x x ( at eq)
Given moles of C :x=2
Hence equilibrium constant = [C][D]/[A][B]
2*2/(1–2)(1–2) = 4
K = 4.,……..by Kritika
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Kundan Agrawal
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Shubham Kumar
Shubham Kumar
Answered Aug 10, 2018
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Ans is 16/3
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