Question

1 mole of a gas occupies volume 1.00x10-2 m3 in a gas cylinder whose pressure is equal to 2.50x105 Pa. The temperature of cylinder is

Answer 1

Answer:

300.69 °K or 27.54 °C.

Explanation:

From ideal gas equation,

PV= nRT.

Temperature (T) = (PxV) / n. R

where R = universal gas constant = 8.314 J/mol. K.

so, temperature (T) = (2.5*10^5*10^-2) / ( 1 * 8.314).

= 300.69 ° K

= 27.54 °C.