Question

1 mole of a gas under the given condition of temperature and pressure have volume 22.4l. By Avogadro's law
$v = k.n$
What is the value of k? Derive value of R,gas constant.​

Answer 1

Answer:

22.4 liter. explantion:-the ideal gas equation relating pressure(P),volume(V),and absolute temperature (T) is given as: pv=nRt R=8.314 mol^-k^-., n=1 mole T =273k. ,P= 1atm =1.013×10^5 so,v=nRt/p.

=1×8.314×273/1.013×10^5.

=0.0224m^3

=22.4liters

Hense,the molar volume of a gas at stp is 22.4 liters