Question

1 mole of an ideal gas at 500K expands isothermally until its volume becomes three

times. Find amount of work done and heat absorbed in the process?

(Use R = 8.3 Jmol-1K-1 and ln 3 = 1.1)​​

Answer 1

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Answer 2

The work done on the isothermal system will be -2739 Joules.

Step-by-step process

Given:

Temperature= 500K

Number of moles = 1

Let the initial volume be $V_{1}$

Then,final volume ;$V_{2}$ = 3$V_{1}$

To find:

Work done

Work done in an isothermal process is given by :

Work done = -nRT ln($V_{2}$ / $V_{1}$)

Putting the values, we get

Work done; W= -1 x 8.3 x 300 ln(3$V_{1}$/ $V_{1}$)

Work done= -2490 x 1.1

Thus Work done on the isothermal system will be -2739 Joules.

The minus sign in -2739 indicates that the reaction is exothermic.