Question

1 mole of an ideal gas at 500K expands isothermally until its volume becomes three

times. Find amount of work done and heat absorbed in the process?

(Use R = 8.3 Jmol-1K-1 and ln 3 = 1.1) (2+1)

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Answer 1

Answer:

5744J

Explanation:

The work done for an isothermal process is given by:

Work done (W)=−nRTln( V2/V1)

Work Done =−1×8.314×300×ln( 250/25)

∴ Work done(W)=−5744J