1 mole of an organic compound on complete combustion produces 88 g of CO2 and 54 g of H2O. If the molar mass of the compound is 46 g, calculate the number of moles of Oxygen atoms present in 368 g of organic compound.
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h2o=54g =3mol=3mol oxygen
co2=88g=2mol = 4mol oxygen
o2 required for burning is 142-46=96g =6mol oxygen
oxygen present in 46g organic compound is
7-6=1mol
there for oxygen present in 368 gram of organic compound =( 368 /46 )*1mol
=8mol
co2=88g=2mol = 4mol oxygen
o2 required for burning is 142-46=96g =6mol oxygen
oxygen present in 46g organic compound is
7-6=1mol
there for oxygen present in 368 gram of organic compound =( 368 /46 )*1mol
=8mol
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