1 mole of calcium trioxocarbonate (v)
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How many moles of calcium carbonate (CaCO
3
) are present in 20 g of the substance?
(Ca=40,C=12,O=16)
Explanation:
Molecular weight of CaCO
3
=40+12+(16×3)=100 g
Given weight =20 g
Therefore no. of moles =
Molecular weight
Given weight
=
100
20
=0.2 moles
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