Question

1 mole of CO2,2 mole of N2,2 moles of O2 were mixed at 300 K ,the entropy of mixing is of

Answer 1

Answer:

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Answer 2

Given the information in the question,

1 mole of Carbon dioxide

2 moles of Nitrogen

2 moles of oxygen at a temperature of 300K

The entropy of the system can be measured by the formula;

ΔS = -n R ∑ xi ㏑ xi

where n represents the total number of moles, R is the universal gas constant and xi represents the mole fraction.

So,

Δ$S_{mix} = (-4) (8.314 J/mol/K) \frac{1}{4} ln (\frac{1}{4} ) + \frac{1}{4} ln (\frac{1}{4} ) +\frac{2}{4} ln (\frac{2}{4} )$

After solving the equation, we will get

ΔS = 34.57 J/K

I hope this should be the answer to your question.

Thank you