Chemistry, asked by dell211, 7 months ago

1 mole of He gas is present in a container of 12 L at 300 K. If a piece of Pt metal having mass 100 g is added in the container at 300 K and pressure of gas becomes 1 atm, the mass of He (approx.) adsorbed per gram of Pt is (Assume volume of Pt piece is negligible and gas is ideal) [Take R = 0.08 atm L/mol K]​

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Answered by fukru2
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Answer:If a piece of Pt metal having mass 100 g is added in the container at 300 K and pressure of gas becomes 1 atm, the mass of He (approx.) adsorbed per gram of Pt is (Assume volume of Pt piece is negligible and gas is ideal) [Take R = 0.08 atm L/mol K]

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