Chemistry, asked by AmiPragga, 17 days ago

1 mole of Helium is heated from 27°C to 327°C at (i) constant pressure (ii) constant volume. Find heat exchange and work done for (i) & (ii).​

Answers

Answered by s1053vandana4854
0

Answer:

Let p be constant pressure, Vi is initial volume, Vf is final volume, n is number of moles and Ti is initial temperature 300 KWorkdone at constant pressure, W = p(Vf - Vi) = p(3Vi - Vi) = 2pVi = 2×n×R×Ti = 2×0.5×8.3×300 = 2.49 kJ

Explanation:

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