1 mole of KClO3 is thermally decomposed n excess of aluminium is burnt in the gaseous product. How many moles of Al2O3 are formed?
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KClO3→KCl+(3/2)O2
4Al+3O2→2Al2O3
dividing the both side by 2 we get
2Al+(3/2)O2→Al2O3
The balanced quations show that 1 mol KClO3≡3/2 mol O2≡1mol Al2O3
4Al+3O2→2Al2O3
dividing the both side by 2 we get
2Al+(3/2)O2→Al2O3
The balanced quations show that 1 mol KClO3≡3/2 mol O2≡1mol Al2O3
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