Chemistry, asked by chahatdia, 8 months ago

1 mole of monoatomic ideal gas expands adiabatically at initial temperature 27° Celsius against a constant external pressure of 0.5 bar from 2 litre to 5 litre the change in enthalpy of process is​

Answers

Answered by navtejp2
0

Answer:

Explanation:

Work done against constant extemal pressure =P  

ext

​  

(V  

2

​  

−V  

1

​  

)  

In adiabatic condition Δq=0  

therefore w=Δu

−P  

ext

​  

(V  

2

​  

−V  

1

​  

)=  

2

3

​  

R(T  

2

​  

−T  

1

​  

)                                [Expansion work is negative]  

On solving, T  

2

​  

=T  

1

​  

−  

3×0.0821

2

​  

Answered by annusingh16
0

Answer:

step by step

plus and multiple take answer and divide 5

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