1 mole of N2 ,3 mol of H2 react with each other in a 4 litre vessel 25 percentage of N2 converted into NH3 find Kc N2g +3h2g----->2nh3
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N
2
+3H
2
⇌2NH
3
t=0 a 3a 0
t=t
eq
(a)(1−α) 3a(1−α) 2aα
Given 50% reacted α=1/2
pNH
3
=(mole fraction)×(total pressure)
=2×α×
2
1
×P=
3
P
=
α×(4−2×1/2)
2×α×
2
1
×P
=
3
P
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