Question

1 mole of N2 and 2 moles of H2 are allowed to react in a 1 cubic dm. At equilibrium, 0.8 mole of NH3 is
formed. The concentration of H2, in the vessel is :
(1) 0.6 mol/L
(2) 0.8 mol/L
(3) 0.2 mol/L
(4) 0.4 mol/L​

Answer 1

Consider that y is the degree of dissociation.

The reaction is

                                                       N2  +  3H2  ⇌  2NH3

Initial moles                                        1          1            0

Number of moles at equilibrium        1-y      1-3y         2y

​At equilibrium the moles of H2 is x

So, 1-3y = x

1-x = 3y

y = (1-x) / 3

Concentration of NH3 at equilibrium is 2y. Put the value of y

Concentration of NH3 at equilibrium = 2(1-x) / 3

The correct option is (3).

​

Answer 2

Answer:

hey mate the correct answer is 3)0.2 mol/L