Question

1 mole of nh3 gas at 27 degree is expanded reversible adiabatic condition to make volume 8 times find the temperature and the work done respectively

Answer 1

Answer:

The answer is 150 K & 900 cal.

Explanation:

Given 1 mole of nh3 gas at 27c is expanded in adiabatic condition to make its volume 8 times( gamma =1.33). final temperature and work done respectively are?

We know that T2 = T1(V1 / V2)^γ - 1

T2 = 300(V / 8 V)^8/6 - 1 ( 273 + 27 = 300 and 8/6 = 1.33)

T2 = 300 (1/8)^1/3

T2 = 300 (1 / (2^3)^1/3)

T2 = 1/2 x 30

T2 = 150 K

Now    W = nRΔt / γ - 1

W = 2 x 150 / 8/6 -

W = 300 / 1/3

W = 900 cal