1 mole of nh3 gas at 27c is expanded in adiabatic condition to make its volume 8 times( gamma =1.33). final temperature and work done respectively are?
Answers
Answered by
39
Answer:
Step-by-step explanation:
Given 1 mole of nh3 gas at 27c is expanded in adiabatic condition to make its volume 8 times( gamma =1.33). final temperature and work done respectively are?
We know that T2 = T1(V1 / V2)^γ - 1
T2 = 300(V / 8 V)^8/6 - 1 ( 273 + 27 = 300 and 8/6 = 1.33)
T2 = 300 (1/8)^1/3
T2 = 300 (1 / (2^3)^1/3)
T2 = 1/2 x 300
T2 = 150 K
Now W = nRΔt / γ - 1
W = 2 x 150 / 8/6 - 1
W = 300 / 1/3
W = 900 cal
Answered by
8
Answer:
Step-by-step explanation: in the attached photo
Ans: 150K
900cal
Attachments:


Similar questions