1 mole of nh3 gas at 27c is expanded in adiabatic condition to make its volume 8 times( gamma =1.33). final temperature and work done respectively are?
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n1 = 1
T1 = 273 + 27 = 300 k
Since the process is adiabatic
So
pressure will be constant
Thus pressure = P
Also V1 = V
Thus P V1 = n1 RT1
P V = R 300
according to question
V2 = 2V
Thus P V2 = n2 R T2
P 2V = R T2
Thus T2 = 600K
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