Question

1 mole of propane ( C3 H8 ) on combustion at STP gives 'A' kilojoules of heat energy . Calculate the heat liberated when 2.4 liter of propane undergoes combustion at STP

Answer 1

Answer:

calculate the heat liberated when 2.4 litres of propane on combustion at STP. so, one mole of propane = 44g. so, 89.2 ml of propane burns to give A kj of energy. = 26.9 A kj of energy.

Explanation:

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