Question

1 mole of propane(C3H8) on combustion at STP gives 'A' kilo joules of heat energy. Caliculate the heat librarated when 2.4 ltrs of propane on combustion at STP?​

Answer 1

Answer:

since we know that every gas occupies 22.4 L at STP then we divide 2. by 22.4

it gives= 1/10 L

Explanation:

Answer 2

Answer:

1 mole at s.t.p is 22.4 litrea so, if 1 mole =22.4 litrestherefore ? = 2.4litres2.4 x 1/22.4 = 0.1071428 moles if one mole of propane = 1KJ therefore 0.1071428 moles = ? 0.1071428 x1/1 therefore 2.4 litres is 0.1071428 KJ

Explanation:

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