Question

1 mole of propane on combustion at stp gives a kilo joules of heat energy calculate the heat liberated when 2.4 litres of propane on combustion at stp

Answer 1

C3H8+5O2 = 3CO2+4H2O+1KJ
1 mole = 22.4liters of propane gives 1KJ of heat energy...
2.4liters of propane gives _ amount of heat energy...
(cross multiplication)
2.4×1/22.4 = 24×1/224/10×10 = 0.10714285