Question

1 mole of propane on combustion at STP gives 'A' kilo joules of heat energy.Calculate the heat liberated when 2.4ltrs of propane in combustion at STP.​

Answer 1

Answer:

1 mole at s.t.p is 22.4 litrea

     so, if 1 mole =22.4 litres

therefore       ?      =  2.4litres

2.4 x 1/22.4 = 0.1071428 moles

 

       if one mole of propane = 1KJ

            therefore 0.1071428 moles = ?

       

           0.1071428 x1/1

    therefore 2.4 litres is 0.1071428 KJ

Hope it helps u !!