Question

1 mole of propane on combustion at stp gives a kilo joules of heat energy calculate the heat liberated when 2.4 litres of propane on combustion at stp

Answer 1

1 mole at s.t.p is 22.4 litrea
      so, if 1 mole =22.4 litres
therefore       ?      =  2.4litres

2.4 x 1/22.4 = 0.1071428 moles
 
        if one mole of propane = 1KJ
             therefore 0.1071428 moles = ?
       
            0.1071428 x1/1

                therefore 2.4 litres is 0.1071428 KJ

Answer 2

1 mole at s.t.p is 22.4 litrea

      so, if 1 mole =22.4 litres

therefore       ?      =  2.4litres

2.4 x 1/22.4 = 0.1071428 moles

 

        if one mole of propane = 1KJ

             therefore 0.1071428 moles = ?

       

            0.1071428 x1/1

                therefore 2.4 litres is 0.1071428 KJ

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