Question

1 mole of SO2 occupies 24 l at room temperature and pressure. calculate the following at the room temperature and pressure:
i) The mass of 6l of SO2
ii) The volume occupied by 80g of SO2
iii) The number of molecules in 0.64g of SO2 if one mole of SO2 contains N molecules.
iv) The weight of 0.5g molecules.
[S=32,0=16]

Answer 1

Answer:

All answers are given below.

Explanation:

1)

Since temperature and pressure are constant. By ideal gas equation

P1V1/n1RT1=P2V2/n2RT2

Since, T1=T2, P1=P2

V1/n1=V2/n2

n2=V2/V1n1

n2=6/24*1=0.25 mole

m/M=0.25

m=0.25*64=16g

So mass is 16 grams.

2)

Since temperature and pressure are constant. By ideal gas equation

P1V1/m1RT1=P2V2/m2RT2

Since, T1=T2, P1=P2

V1/m1=V2/m2

V2=V1m2/m1

V2=24*64/80= 19.2  L

So volume occupied by 80 gram of SO2 is 19.2 L.

3)

Given mass = m = 0.64 g

Molar Mass = M = 64 g

No. moles = m/M=0.64/64=0.01 moles

No, of molecules = 0.01N

4)

W = mg

W = 0.5*10 = 5 N

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