1 molelphur dioxide occupies 24dm^3 at room temperature and pressure .calculate at rtoom temperature and pressure.
(1) mass of 6 dm^3 of sulphur dioxide gas (2)volume occupied by 80g of sulphur dioxide (3)molecules in 0.64 g of sulphur dioxide ,if 1 mole of sulphur dioxide contains N molecules
(4)weight of 0.5g molecu;les of sulphur dioxide
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Answer:
(1)9.6352×10^24
Explanation:
(1) we know that n=W/M
here 6dm^3 of gas=1/4 mol.
Molar Mass of SO2=64 amu
therefore Weight of SO2=(1/4)×(64)×avogadro number
=16×6.022×10^23
=9.653×10^24
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