Question

1)Mrs. Thapa bought 150 kg of oranges. 18 kg of oranges were rotten and not fit for selling. If she sold the remaining quantity of oranges at the rate of Rs 80 per kg and gained 10%, find the rate of cost price or oranges.​

Answer 1

Answer:

Let the no. of oranges purchased be 100

Let the Cost of 1 orange be one rupee

Hence, cost of 100 oranges is Rs. 100/-

LOT 1

Given, Selling price (S.P) of 50 oranges is Rs. 100/-

Profit % = (sp-cp)/cp*100

Profit % = (100 - 50)/50* 100 = 100%

LOT 2

No. of oranges sold in 2nd lot, 60% of balance 50% = 30 nos

Half of earlier profit = 100/2 = 50%

S.P of 30 oranges = 30* 150% = Rs. 45/-

LOT 3

S.P of thrown away 20 oranges = 0

(100 - 50 - 30)

Answer:

Hence, profit % will be

Profit % = (sp-cp)/cp*100

= {(100+45+0) - 100}/100*100

= 45 %

Step-by-step explanation:

Answer 2

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