Math, asked by shankar1232, 1 year ago

1. Mukesh purchased two watches at the same price and sold one at a profit of 20
% and the other at a profit of 22.5 %. If the difference between the two selling
price is Rs.150. What is the cost price of the watch.​

Answers

Answered by uday7358
0

Answer:

Watch1=1200

Watch2=1050

Step-by-step explanation:

let Cp -x

case-1=

Cp -x

Profit =22.5%

Sp=(100+22.5/100)*x=1.225x

Case-2=

Cp = x-150

Profit-20%

Sp-(100+20/100)*(x-150)=1.20*(x-150)

ATQ

1.225x-1.20(x-150)=150

1.225x-1.20x+180=150

0.025x=-30

25/1000x=-30

x=-30*1000/25

x=1200

Cp of first watch = 1200

Cp for second watch = 1200-150=1050

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