Math, asked by srijanarai1048, 12 hours ago

1. Multiple Choice Questions (MCQs): 1 x 4 = (i) The expression 4 pq which is expressed as the difference of the squares of two expressions is ?

Answers

Answered by ojhaanand279
5

Answer:

Correct option is

B

2nπ−

4

π

Given

2

secx+tanx=1

cosx

2

+

cosx

sinx

=1

(secx=

cosx

1

,tanx=

cosx

sinx

)

2

+sinx=cosx

⟹cosx−sinx=

2

2

1

cosx−

2

1

sinx=1

⟹cos

4

π

cosx−sin

4

π

sinx=cos0

⟹cos(

4

π

+x)=cos0

(cos(A+B)=cosAcosB−sinAsinB)

⟹cos(

4

π

+x)=cos0

4

π

+x=2nπ

(cosk=0⟹k=2nπ)

⟹x=2nπ−

4

π

Answered by pulakmath007
3

SOLUTION

CORRECT QUESTION

The expression 4pq which is expressed as the difference of the squares of two expressions is

EVALUATION

Here the given expression is 4pq

Now we express it as the difference of the squares of two expressions as below

\sf 4pq

\sf = 2pq - ( - 2pq)

\sf =( {p}^{2} + {q}^{2} + 2pq )- ({p}^{2} + {q}^{2} - 2pq)

\sf =( {p}^{2} + 2pq + {q}^{2} )- ({p}^{2} - 2pq+ {q}^{2})

\sf =( {p}^{2} + 2.p.q + {q}^{2} )- ({p}^{2} - 2.p.q+ {q}^{2})

\sf ={(p + q)}^{2} - {(p - q)}^{2}

FINAL ANSWER

\sf 4pq={(p + q)}^{2} - {(p - q)}^{2}

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