Question

1. Multiply the binomials:
1 (x + 2) (x + 3)
(iv) (3y + 8) (3y - 8)
(v) (a - b)(a + b)
(vi) (6-3) (2p - 7)
(viii) (5p + 39) (3p - 49)
(1) (x2 + 3)(x2 - 4
(vi) (2x - 5) (x + 3)​

Answer 1

Answer:

(x+2)(x+3)

=x^2+3x+2x+6

=x^2+6x+6

(3y+8)(3y-8)

=(3y)^2-(8)^2

=9y^2-64

(a+b)(a-b)

=(a)^2-(b)^2

=a^2-b^2

(6-3)(2p-7)

=3(2p-7)

=6p-21

(5p+39)(3p-49)

=15p^2-245p+117p-1911

=15p^2-128p-1911

(x2+3)(x2-4)

=x^4-4x+3x^2-12

=x^4+3x^2-4x-12

(2x-5)(x+3)

=2x^2+6x-5x-15

=2x^2+x-15

Step-by-step explanation:

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