1. Multiply the following and write your answer in lowest terms
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Solution :
[(x²-2x)/(x+2)] × [(3x+6)/(x-2)]
= [x(x-2)/(x+2)] × [3(x+2)/(x-2)]
= [x(x-2) * 3(x+2)]/[(x+2)(x-2)]
After cancellation ,
= 3x
••••
[(x²-2x)/(x+2)] × [(3x+6)/(x-2)]
= [x(x-2)/(x+2)] × [3(x+2)/(x-2)]
= [x(x-2) * 3(x+2)]/[(x+2)(x-2)]
After cancellation ,
= 3x
••••
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