Question

1. Mustard gas, used in chemical warfare in World War I, has been found to be an effective
agent in the chemotherapy of Hodgkin’s disease. It can be produced according to the
reaction: SCl2(g) + 2C2H4(g) ↔ S(CH2CH2Cl)2(g).
An evacuated five-liter flask at 20.0oC is filled with 0.258 mol of SCl2 and 0.592 mol C2H4.
After equilibrium is established, 0.0349 mol of mustard gas is present.
a. What is the partial pressure of each gas at equilibrium?
b. What is K at 20oC?

Answer 1

Mustard gas, used in chemical warfare in World War I, has been found to be an effective

agent in the chemotherapy of Hodgkin’s disease. It can be produced according to the

reaction: SCl2(g) + 2C2H4(g) ↔ S(CH2CH2Cl)2(g).

An evacuated five-liter flask at 20.0oC is filled with 0.258 mol of SCl2 and 0.592 mol C2H4.

After equilibrium is established, 0.0349 mol of mustard gas is present.

a. What is the partial pressure of each gas at equilibrium?

b. What is K at 20oC?

I don't know the answer of this question