Math, asked by VisHalwai, 10 months ago

1/n!-1/(n-1)!-1/(n-2)!​

Answers

Answered by Anonymous
16

Step-by-step explanation:

Step-by-step explanation:

1/n(n-1)(n-2)! -1/(n-1)(n-2)! -1/(n-2)! =0

1(n-2)! [1/n(n-1) -1/(n-1) -1] =0

taking LCM

1-n-n(n-1)/n(n-1)=0

1-n-n^2+n/n(n-1)=0

-(n^2-1^2)/n(n-1)

-(n-1)(n+1)/n(n-1)

-(n+1)/n

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