Question

1.n(A)+n(A')= 2.n(A)+n(B)-n(AnB)= 3.n(B)-n(AnB)= IN SETS ANSWER ONLY IF YOU KNOW THE ANSWER OR ELSE I WILL REPORT IT PLEASE THIS IS IMPORTANT .. DON'T SPAM..I need correct answer​

Answer 1

Answer:

Here from vendiagram

n(a-b) =n(a)-n(anb)

And, n(b-a) =n(b)-n(anb)

Again from vendiagram we get 1 formula

n(aub)=n(a-b)+n(b-a)+n(a-b)

n(aub)=n(a)+n(b)-n(anb) [putting the value of n(a-b), n(b-a) ]

Answer 2

Answer:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2