Question

1)Name the above process.
2) Name the electrodes used as cathode and anode
3) Reaction at Anode.
4) Reaction at cathode
5) Products formed at cathode and anode.​

Answer 1

Answer:

Explanation:

This is the cation and anion process.

Both Anode and Cathode are used Negative Electrodes.

At anode the copperours oxides will form.

At cathode the mendelevium sulphate at negative electrodes will forms .

Me + CuSO₄ ↔ MeO + CuO + SO₂(g).