Question

1
node and
Q: What is distance b/w
and antinode
of a stationary
wave of frequency 1000Hz if
speed
of sound is
300m/s?​

Answer 1

Answer:

Given that,

Speed of sound in air is 300 m/s.

Frequency of wave, f = 1000 Hz

We need to find the distance between two successive nodes of a stationary wave. The speed of a wave is given by :

v=f\lambdav=fλ

\lambda=\dfrac{v}{f}λ=

f

v

\lambda=\dfrac{300}{1000}λ=

1000

300

\lambda=0.3\ mλ=0.3 m

or

\lambda=30\ cmλ=30 cm

So, the distance between two successive nodes of a stationary wave is 30 cm. Hence, this is the required solution.

Learn more,

Speed of a wave

Answer 2

Answer:

its 500ms and 200hz and Its distance lol