1)non -working :to verify the conditions of consistency and inconsistancyby graphical method
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Procedure:
1. Consider a pair of linear equations of the form
a1x+b1y+c1a2x+b2y+c2==00
a1,a2,b1,b2,c1 and c2 are real numbers and not simultaneously 0.
Consider following cases:
Case I:
x+y2x+3y==46
Here, a1a2≠b1b2
Case II:
2x+y4x+2y==48
Here, a1a2=b1b2=c1c2
Case III:
x−y2x−2y==26
Here, a1a2=b1b2≠c1c2
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Answer:
here 26 is the correct answer pls mark me as brainlist pls ❤️❤️
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