Question

1. Number of electrons, protons and neutrons present in 17Cl35, 17Cl37 is- -------------- a) 17e¯ , 17p+, 17n 17e¯ , 17p+, 19n b) 18e¯ , 18p+, 17n 17e¯ , 20p+, 19n c) 17e¯ , 17p+, 18n 17e¯ , 17p+, 20n d) 18e¯ , 17p+, 18n 20e¯ , 20p+, 17n​

Answer 1

Answer:

atomic number gives the value of number of protons or number of electrons .

mass number is the sum of number of protons and neutrons.

so, for 17Cl35, p=17,e=17,n=M-p=35-17=18.

for 17Cl37, p=17,e=17,n=M-p=37-17=20.

option c is the answer.