Question

1. Number of milligrams of KOH required to neutralize fatty acid present in 1 gram of fat is
called .....
(a) Acid Number
(b) Potassium Number
(c) Saponification Number
(d) Iodine Number​

Answer 1

Answer:

a) acid value

if koh saponify fatty acid present in 1 gm of fat, then it is called saponification number.

Answer 2

Number of milligrams of KOH required to neutralize fatty acid present in 1 gram of fat is called Saponification Number.(Option-C)

• The reaction of potassium hydroxide KOH with fatty acids is a type of saponification reaction.
• In a saponification reaction, some alkali bases like potassium hydroxide KOH react with fatty acids, lipids, or oil molecules to produce ester salts of long-chain fatty acids and alcohol as the end product of the reaction.
• This is a type of esterification reaction and the ester salts of long-chain fatty acids, that are obtained as the end products of this reaction, firms the soaps. Hence, this reaction is called the saponification reaction.
• Consequently, the number of milligrams of the alkali base (KOH in this case) required to neutralize the fatty acids or lipids present in 1 gram of fat is denoted as its saponification number.
• That's why the saponification number is the correct answer to this question.