Question

1 number twice more than second number by 6 find the number

Answer 1

Answer:

Let X be one number and Y be the second number.

X minus Y = 6

X plus Y = 16

as equations:

X-Y=6

X+Y = 16

Solving for X in the first equation by substitution

Adding Y to both sides yields

X-Y+Y = 6+Y

X= 6+Y

Substituting 6+Y for X in the second equation yields

6+Y +Y = 16

2Y+6 = 16

Solving for Y by subtracting 6 from both side of the equation keeps it “equal”

2Y+6–6 = 16–6

2Y = 10

Y=5

Substitute 5 for Y in either of the original equations yields:

X-5 = 6

X-5+5=6+5

X=11

Therefore X is a positive 11 and Y is a positive 5

11–5=6

11+5=16!