1 numerical based on kinetic energy to potential energy
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A body of mass = 10 kg
is on a height of = 10 m
gravitational force = 10m/s²
Now, potential energy = mgh = 10 * 10 * 10 = 1000 J
Is dropped so there will be velocity
then, v² - u² = 2gh
v² = 2 * 10 * 10 = 200
so,v = 10√2 m/s
so, kinetic energy = 1/2mv² = 1000 J
is on a height of = 10 m
gravitational force = 10m/s²
Now, potential energy = mgh = 10 * 10 * 10 = 1000 J
Is dropped so there will be velocity
then, v² - u² = 2gh
v² = 2 * 10 * 10 = 200
so,v = 10√2 m/s
so, kinetic energy = 1/2mv² = 1000 J
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0
Answer:
The answer is wrong correct answer i will give you later.
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