Question

1.
Observe the following sequence:
(1), (3+5), (7+9+11). (13+15+17+19), (21+23+25+27+29).....
Consider each bracket to be one term. Find the value of
(1) 15th term (11) 36th term of the sequence.​

Answer 1

Answer:

it is in the form of Cubes 1,8,27

is 15 Cube=15X15X15=3375

36x36x36=46656

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