Math, asked by kavinfidel, 11 months ago

(1-omega)(1-omega^2)(1-omega^4)(1-omega^8)=?​

Answers

Answered by sandy1816
17

Step-by-step explanation:

(1-ω)(1-ω²)(1-ω⁴)(1-ω^8)

=(1-ω)(1-ω²)(1-ω³.ω){1-(ω³)².ω²}

=(1-ω)(1-ω²)(1-ω)(1-ω²)

=(1-ω)²(1-ω²)²

={(1-ω)(1-ω²)}²

={1-ω²-ω+ω³}²

={1+(-ω-ω²)+ω³}²

={1+1+1}² [1+ω+ω²=0]

=9

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Answered by nandiniilayaraja
5

Answer:

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Thank you.

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