(1-omega)(1-omega^2)(1-omega^4)(1-omega^8)=?
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17
Step-by-step explanation:
(1-ω)(1-ω²)(1-ω⁴)(1-ω^8)
=(1-ω)(1-ω²)(1-ω³.ω){1-(ω³)².ω²}
=(1-ω)(1-ω²)(1-ω)(1-ω²)
=(1-ω)²(1-ω²)²
={(1-ω)(1-ω²)}²
={1-ω²-ω+ω³}²
={1+(-ω-ω²)+ω³}²
={1+1+1}² [1+ω+ω²=0]
=9
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5
Answer:
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