(1+omega-omega^2)-(1+omega+omega^2)
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Answer:
ω3=1
Step-by-step explanation:
(1−ω+ω2)(1+ω−ω2)
=((1+ω2)−ω)(1+ω−ω2)
=(−ω−ω)(−ω2−ω2)
=(−2ω)(−2ω2)
=4ω3=4
Where 1+ω+ω2=0 and ω3=1
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