Math, asked by sunilraghav01061970, 8 months ago

(1-omega-omega^2)^6=64​

Answers

Answered by kpratyush89
1

Answer:

(1-Ω-Ω²)⁶=64

=>(1-Ω-Ω²)⁶=2⁶

=>(1-Ω-Ω²)=2

=>-1-Ω-Ω²=0

=>1+Ω+Ω²=0...... multiplying both sides by (-1)

=>Ω²+Ω+1=0

=>Ω=-1±√(1²-4×1×1)÷2×1

=>Ω=(-1±√3¡÷2)

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