Question

(1) One die is rolled,

Event A : Even number on the upper face.

Event B : Odd number on the upper face.

Event C: Prime number on the upper Face​

Answer 1

Answer:

1. P(A) = $\frac{1}{2}$
2. P(B) = $\frac{1}{2}$
3. P(C) = $\frac{1}{2}$

Explanation:

Given:

A die is rolled

To find:

The probability of:

1. Event A : Getting an even number on the upper face.
2. Event B : Getting an odd number on the upper face.
3. Event C: Getting a prime number on the upper Face​

Proof:

According to the question,

1. Total number of outcomes = 6

• 1
• 2
• 3
• 4
• 5
• 6

  Number of favourable outcomes = 3

• 2
• 4
• 6

∴ P (A) = $\frac{No. of favourable outcomes}{Total number of possible outcomes}$

           = $\frac{3}{6}$

           = $\frac{1}{2}$

2. Total number of outcomes = 6

• 1
• 2
• 3
• 4
• 5
• 6

    Number of favourable outcomes = 3

• 1
• 3
• 5

∴ P (B) = $\frac{No. of favourable outcomes}{Total number of possible outcomes}$

           = $\frac{3}{6}$

           = $\frac{1}{2}$

3. Total number of outcomes = 6

• 1
• 2
• 3
• 4
• 5
• 6

    Number of favourable outcomes = 3

• 2
• 3
• 5

∴ P(C) =  $\frac{No. of favourable outcomes}{Total number of possible outcomes}$

           = $\frac{3}{6}$

           = $\frac{1}{2}$

Hope you got that.

Thank you.