Question

1 One number is 9 less than three times a second number. If the first number plus twice the second number is 16. Find the two numbers. A rectenoular house has a perimeter of 80 metres and the length is 4 metres more​

Answer 1

Answer:

A=3B-9

A+2B=16

Substitute for a,

{3B-9}+2B=16

5B=25

8=5

Then,

A=3•{5}-9

A=15-9

A=6