Question

1
One of the roots of equation x²+mx- 5 = 0 is 2;find m.

(A) -2
(B)-½
(C)½
(D) 2
​

Answer 1

Answer:

(C) ½

Step-by-step explanation:

Given:-

First Root = 2

Now

$f(x) = {x}^{2} + mx - 5 = 0$

Put x = 2 in f(x)

$f(2) = {2}^{2} + 2m - 5 = 0$

$= > 4 + 2m - 5 = 0$

$= > 2m - 5 = - 4$

$= > 2m = - 4 + 5$

$= > 2m = 1$

$= > m = 1 \div 2$

$= > m = 0.5$

So Answer is m = ½

Hope it helps.

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Answer 2

I'd: 1042770716 of Free fire