Question

1) one of the two digit of a two digit number is three times the other digit. If you interchange the digit of this two digit number and add the resulting number to the original number, you get 88. what is the original number?​

Answer 1

Answer:

26 or 62

Hope it helps you.........

Answer 2

Answer:

Let one digit be x.

Let one digit be x.So, the other digit is 3x.

Let one digit be x.So, the other digit is 3x.The number formed will be 10×x + 3x.

Let one digit be x.So, the other digit is 3x.The number formed will be 10×x + 3x.=10x+3x

Let one digit be x.So, the other digit is 3x.The number formed will be 10×x + 3x.=10x+3x=13x.

Let one digit be x.So, the other digit is 3x.The number formed will be 10×x + 3x.=10x+3x=13x.After interchanging the digits we get the number as

10×3x + x

10×3x + x=30x + x

10×3x + x=30x + x=31x.

By the given condition

13x + 31x = 88

13x + 31x = 8844x = 88

13x + 31x = 8844x = 88X = 2.

13x + 31x = 8844x = 88X = 2.So, the number formed is 10×2 +3×2 = 20+6=26.

Also the number can also be 62

Please Mark it Brainliest